this post was submitted on 15 Mar 2025
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Science Memes

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[–] pseudo@jlai.lu 3 points 1 day ago

Thank you OP!

[–] Trollception@sh.itjust.works 2 points 1 day ago (1 children)

Uhh who's joking about identify theft?

[–] Akasazh@feddit.nl 4 points 1 day ago

Your username is incredibly apt here

[–] MichaelScotch@lemmy.world 13 points 2 days ago (2 children)

Identity theft is not a joke, Jim. Millions of families suffer every year. Also one that the internet gets wrong all the time: “dude, this is a Wendy’s”, not “sir this is a Wendy’s”

[–] subtext@lemmy.world 3 points 1 day ago (1 children)

I believe it’s actually, “dude, this is a Wendy’s restaurant.” Check and mate.

[–] MichaelScotch@lemmy.world 2 points 1 day ago

Well done sir, well done… I mean dude

[–] massive_bereavement@fedia.io 4 points 2 days ago

Bernstein bears

[–] neidu3@sh.itjust.works 37 points 2 days ago* (last edited 2 days ago) (6 children)

Could one of you scholars please explain the joke for us smoothbrains who don't get it? All I see is a boolean matrix, and I'm not even sure that is correct.

[–] pseudo@jlai.lu 14 points 1 day ago* (last edited 1 day ago) (1 children)

That matrix of zeros with one in diagonal is called the matrix of identity.
It is famous because when doing multiplication on matrix or vector, it acts likes 1 on "normal" number:
x times 1 is x anyMatrix times Identity is anyMatrix.

[–] fallingcats@discuss.tchncs.de 5 points 1 day ago (2 children)

Wouldn't you need to put anyMatrix first, since matrix multiplication isn't commutative?

[–] MBM@lemmings.world 1 points 1 day ago

Huh? Identity times anyMatrix is also anyMatrix. The matrix just has to have the right dimensions

[–] pseudo@jlai.lu 3 points 1 day ago (1 children)

You are right. I will correct it.

[–] fallingcats@discuss.tchncs.de 1 points 1 day ago* (last edited 21 hours ago) (1 children)

No I just tried it and I was wrong, it seems like it doesn't matter for the ID matrix specifically

[–] pseudo@jlai.lu 1 points 1 day ago

I need to freshen up on my linear algebra. I don't remember on which sense it goes but I think if you swap the factors, you'll have to you transpose the matrix x to keep the same result.

[–] Saleh@feddit.org 5 points 1 day ago

You multiply vectors and matrizes row by column.

So for any matrix the fitting identity matrix multiplies each row on the relevant position by one and puts it into a column.

The matrix remains the same.

See example 5 here: https://www.geeksforgeeks.org/identity-matrix/

[–] Gustephan@lemmy.world 14 points 1 day ago

Eigen see how this is confusing, I don't get it either

[–] ryedaft@sh.itjust.works 2 points 2 days ago

It's like if you multiply or divide by one. Just a bit bigger cuz linear algebra.

[–] lugal@lemmy.dbzer0.com 41 points 2 days ago

It's an identity matrix. You multiple a vector with it and the result is still the same (identical) vector

[–] zqwzzle@lemmy.ca 69 points 2 days ago

A square matrix with the ones in the diagonal is called the identity matrix

[–] NocturnalMorning@lemmy.world 3 points 2 days ago

At least they're symmetric.