this post was submitted on 15 May 2025
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[–] [email protected] 5 points 6 days ago* (last edited 5 days ago) (2 children)

So the fifth person to arrive moves to the centre of the tetrahedron and shifts roughly 1.299m into the past or future.

I have a few questions.

  1. How do you attain time offset?
  2. Doesn't that make conversation difficult?
  3. What even is the fifth dimension?
  4. How do you convert a distance in metres into a distance in time? You would surely then have a universal m/s? Oh, wait, there is a universal speed, it's the speed of light, which means 1.299m is equivalent to about 4.3 billionths of a second, which is considerably less impressive for question 1 and just not at all problematic for question 2.
  5. If you're using very fast motion for your time offset, doesn't that make conversation even more difficult? How fast would you need to be going to dilate time for a few billionths of a second? Doesn't Heisenberg uncertainty start to have an impact here? How can you be sure you got it right?
[–] [email protected] 2 points 5 days ago (1 children)
  1. So, the diagram doesn't represent it well, but the 1.5m is a minimum. So, I just delay myself by half a heartbeat which is well over 4.3^e-9s.
[–] [email protected] 2 points 5 days ago (1 children)

Yes, but if they're just minimums, there's no need for even using the third dimension, let alone the fourth.

[–] [email protected] 1 points 5 days ago (1 children)

Oh, I may have violated distancing protocols then. My personal delay device doesn't have sub-microsecond accuracy. Should I will have gotten a test for time-invariant COVID ?

[–] [email protected] 2 points 5 days ago

I won't tell if you won't tell.

[–] [email protected] 4 points 5 days ago (1 children)

If you have to ask, you wouldn't understand.

[–] [email protected] 3 points 5 days ago

If I understood, I wouldn't have to ask.