I'm just gonna start swolping my arms out pulling all levers, fuck it

The one, that seems to be closest

id pull the right one

Help me, I assumed that it's possible but then two men appeared to decompose the train and put the parts back together into two copies of the original train

Get a time machine that can take me infinitely toward and backward in time, then use an infinitely long piece of string to attached to one lever in each cluster, then pull all the levers at once to redirect the train.

Irrelevant

You will never be in time to pull an infinite amount of levers before the trolley runs those people over

The image suggests that a closest element of each cluster exists, but a furthest element does not, so I will pull the closest lever in each cluster.

sortition all the way

i open the I Ching

I like the axiom of determinacy more than the axiom of choice.

Can I take the axiom of choice?

I invoke the axiom of choice and hope for the best. because if it doesn't work we have bigger problems then 4 dead people

Just pull out a few thousand levers and throw them in front of the trolley.

I know you can't enumerate them all, but you just have to enumerate them faster than the trolly. and live forever

Just pull every one, I know one in each cluster will work, but like I gotta make sure

Since any one will work I just pull a nearby lever at random and go home

That one

Too complicated I'm just going to walk away

I would just pick the value from the root of each underlaying balanced binary tree, easy.

I select the most proximate lever in each cluster, using any criteria that would produce a beginning of a discrete order (so no ties for first). If I get infinite "tries" then even if it is an infinitesimally small chance of selecting the functional lever, at some point I will expect to get it.

Yo this sounds suspiciously similar to how quantum resistant lattice cryptography works.