this post was submitted on 15 May 2025
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Equal sides in a triangle are only possible if the corners are equal. So, 60⁰ each.
But its height cannot be half of base because of the same Pythagorean theorem
(1,5)²+(1,5/2)²=2,8125
sqrt(2,8125) ≈ 1,677, which is half of a diagonal
So, we get 4 sides that are 1,5 in a parallelogram, but diagonals are 1,5 and 3,354, as opposed to both being 1,5 as shown on the picture
TL;DR: Won't work because Pythagorean theorem
Pyramid?
Wdym?
They could each be on the vertices of a tetrahedron for all we know...
We do know that, with those measurements, they aren't confined to a single (Euclidean) plane.
Exactly! I regret that I have but one upvote to give.
I was thinking of plane surfaces, but if their altitudes are different, I guess it'd be possible.