this post was submitted on 08 Nov 2024
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You still have to check that it's sorted, which is O(n).
We'll also assume that destroying the universe takes constant time.
Well yeah just delete the pointer to it!
universe.take()In the universe where the list is sorted, it doesn't actually matter how long the destruction takes!
It actually takes a few trillion years but its fine because we just stop considering the "failed" universes because they will be gone soon™ anyway.
Eh, trillion is a constant
amortized O(0)