this post was submitted on 25 Mar 2024
85 points (96.7% liked)
[Outdated, please look at pinned post] Casual Conversation
6593 readers
1 users here now
Share a story, ask a question, or start a conversation about (almost) anything you desire. Maybe you'll make some friends in the process.
RULES
- Be respectful: no harassment, hate speech, bigotry, and/or trolling
- Encourage conversation in your post
- Avoid controversial topics such as politics or societal debates
- Keep it clean and SFW: No illegal content or anything gross and inappropriate
- No solicitation such as ads, promotional content, spam, surveys etc.
- Respect privacy: Don’t ask for or share any personal information
Related discussion-focused communities
founded 1 year ago
MODERATORS
you are viewing a single comment's thread
view the rest of the comments
view the rest of the comments
Taylor series approximations work because the derivatives of the taylor series expansion and the function it is approximating are the same (and the values at the given point). Likewise, the derivative of e^x is e^x because the taylor expansion of e^x is 1 + x/1! + x^2/2! + x^3/3!... which becomes 0 + 1 + x/1! + x^2/2! + x^3/3!... when the derivative is taken. So the derivative of the taylor expansion of e^x is itself.