The answer could be however many beats the longest note is at however many BPM you choose given that 60 is a large enough number to cover each pitch and quality of note in the piece. Having all the essential notes and durations covered, the rest is just inessential noodling left as an exercise for the reader.
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Most speedrunners know about the glitch in Beethoven's 9th where if you have the entire brass section make a quarter turn to the left at just the right moment of the open fifths the whole symphony freezes for a second and then drops you straight into the Ode to Joy.
If that's not how it works then why is his 3rd symphony three times as long as his 1st?
Something something nine women something one month.
sacrilegious
INTERESTING
It got buffed. Lower ttk
The real answer is 70-80min, because that's just how long the 9th symphony takes to be played. And they better add a chorus as well, otherwise the 4th movement won't be as good as it normally is
The question never states that the relationship t(p) would be a linear function of p
Exactly; t(p)=40.
As I was going to St. Ives I met a man with seven wives. Each wife had 7 sacks, each sack had 7 cats, each cat had 7 kits. Kits, cats, sacks, wives; how many were going to St. Ives?
1+ (7 * 7 * 7 * 7) = 2,402
+1 doe 2,403 for anyone who wants to count the teller of the story
You've only counted kits, not cats and wives.
He's still wrong. The answer is 1.
Well, the answer is "at least 1". We don't know the destination of the polygamist or whether there were other travellers with less remarkable entourages.
St. Ives is a popular tourist destination, but stupidly remote and takes a long time to reach. It's likely that there are several people travelling to St. Ives at any given moment.
This is a stupid riddle, because maybe they were walking in the same direction. I'd expect the guy with all the wives and cats to be making slower progress, you know?
You and your mum...
duh duh duh SPLAT!
Assume a spherical oboist...
I see you've met my oboist
(P=120 ∧ T=40 ∧ ¬(P∝T))⇒(P=60 ⇒ T=40)