So do I need both hands to count all the gold atoms? ^
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Once a lead nucleus has transformed by losing protons, it is no longer on the perfect orbit that keeps it circulating inside the vacuum beam pipe of the Large Hadron Collider. In a matter of microseconds it will collide with the walls.
This effect makes the beam less intense over time. So for scientists, the production of gold at the collider is in fact more of a nuisance than a blessing.
*sigh* "Send in the janitor to scrape the gold off the walls. Bloody gold is disturbing our equipment again!".
This sounds like something Cave Johnson would say in Portal 2 lol
I can understand how such tech would be valuable for the electronics industry. I wonder if they’d be able to turn lead into copper? Or something else? It’s an interesting thought.
Interesting thought, yeah, but this method isn't going to be viable for mass production, possibly ever.
They produced 89000 nuclei per second.
1 gold atom weighs about 196.96657 u.
1 u is 1.66053906892 * 10^−27^ kg.
Therefore, we can calculate how much gold they'd produce in a year:
196.96657 u/atom * 1.66053906892*10^−27^ kg/u * 89 000 atoms/second * 60 seconds/minute * 60 minutes/hour * 24 hours/day * 365 days/year = 917.9905991879 * 10^-15^ kg/year
That's still basically nothing. If they ran these streams continuously for a billion years, that's when we'd get close to producing 1 gram.
And it won't really start scaling much either, since you'll always need to accelerate a proportional amount of lead to near-light-speed, no matter what you produce with this method. But yeah, maybe we'll find a different method at some point.
The gold also doesn't last. It's quickly obliterated by downstream processes
You'd theoretically be able to turn one lead atom into two copper atoms and an atom of Maganese based on proton counts