What's the correct value if the answer is not picked at random but the test takers can choose freely?
this post was submitted on 06 May 2025
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But what's the question?
how many roads must a man walk down?
What is six times nine
Close, but nah, it's the meaning of life
nuh uh, it's the answer. to life, the universe, everything! Um, but what's the question?
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It's probably graded by a computer, and a) or d) is a fake answer, since the automated system doesn't support multiple right answers.
I'm going to go with 25% chance if picking random, and a 50% chance if picking between a) and d).
If it's graded by a human, the correct answer is f) + u)
Many systems do allow multiple correct answers.
Paradoxes aside, if you're given multiple choices without the guarantee that any of them are correct, you can't assign a chance of picking the right one at random anyway.
I see 25% twice so my bet is on 50%.
But 50% only appears once, which would make the answer 25%.
The question is malformed and the correct answer isn't listed in the multiple choices. Therefore the correct answer is 0%
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C, which means A or D, which means C, which means...
Lisa stays home?
There is absolutely no way it is 60%. Because you can never have 60% chances of picking anything particular when there are only 4 choices. Knowing this, the answer is either 25% or 50%. Two effective choices, so the answer is C, 50%.
If C is the correct choice, then that is only one answer out of four that is correct, meaning you only had a 25% chance to answer correctly. You've created a logical paradox.
25% occurs twice, so in reality there are only 3 outcomes from your pick. Since you know 25% is incorrect from this, that is 30% of the total answers, but also 50% of total options. Via this, you can conclude that both b and c are valid answers, depending on whether you view it in relation to outcomes or in relation to options. If you view the 3 outcomes, then you have a 60% chance of being right, but if you view the 4 options, you have a 50% chance of being right. Both 50% and 60% being accepted as anwswers solves the paradoxical nature of the question.
If I'm choosing at random between 50% and 25%, then I have 50% chance to get 50%. It is random, but I eliminate the weird options.
I do that sometimes.
the key word here is at random, you imagine a situation where you're doing it at random, but you're not actually answering randomly are you?
Even at random, 25% chance are the only options that are wrong, and they account for 50% of the choices and 30% of the true options. Otherwise, the question has no correct answer due to the two 25%s.
One caviat of course is that in reality, 2/3 is 66.6% and not 60%, but ya kno.