this post was submitted on 19 Nov 2024
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[–] [email protected] 12 points 19 hours ago (1 children)

Maybe my math is wrong but: The Earth's radius is about 6,371 kilometers. With this large radius and a 24-hour rotation period, the centripetal acceleration at the equator is only about 0.034 m/s². This is tiny compared to Earth's gravitational acceleration of 9.8 m/s². So the centripetal effect is only about 0.3% of gravity's effect.

[–] [email protected] 2 points 17 hours ago* (last edited 17 hours ago) (1 children)

40,075,000m circumference / 86,400s = 463m/s?

[–] [email protected] 5 points 16 hours ago* (last edited 16 hours ago)

Yes, that is the speed you're going, then the acceleration you experience due to the change in direction as the earths surface revolves about an axis is a = v²/r. R being the radius of the earth. This gets us our small acceleration value.

You do experience this small acceleration as a very small reduction in weight. You actually weigh more at the poles than the equator. You don't feel the velocity at all, as the whole planet is moving with you.