this post was submitted on 07 Jul 2025
1 points (100.0% liked)

Shell Scripting

1496 readers
2 users here now

From Ash, Bash and Csh to Xonsh, Ysh and Zsh; all shell languages are welcome here!

Rules:
  1. Follow Lemmy rules!
  2. Posts must relate to shell scripting. (See bottom of sidebar for more information.)
  3. Only make helpful replies to questions. This is not the place for low effort joke answers.
  4. No discussion about piracy or hacking.
  5. If you find a solution to your problem by other means, please take your time to write down the steps you used to solve your problem in the original post. You can potentially help others having the same problem!
  6. These rules will change as the community grows.

Keep posts about shell scripting! Here are some guidelines to help:


In general, if your submission text is primarily shell code, then it is welcome here!

founded 2 years ago
MODERATORS
 

Let me show you what I mean by giving an example:

# Assume we have this list of increasing numbers
140
141
145
180
190
...

# If we pick 150 as threshold, the output should consist of 145 and all larger values:
145
180
190
...

# In the edge case where 150 itself is in the list, the output should start with 150:
150
180
190
...

I guess one can always hack something together in awk with one or two track-keeper variables and a bit of control logic. However, is there a nicer way to do this, by using some nifty combination of simpler filters or awk functionalities?

One way would be to search for the line number n of the first entry larger than the threshold, and then print all lines starting with n-1. What command would be best suited for that?

Still, I'm also wondering: Can awk or any other standard tool do something like "for deciding whether to print this line, look at the next line"?

(In my use case, the list is short, so performance is not an issue, but maybe let's pretend that it were.)

you are viewing a single comment's thread
view the rest of the comments
[–] [email protected] 0 points 2 days ago* (last edited 2 days ago) (3 children)

For the simpler case of threshold match and larger, with the list already ordered, you could use sed:

echo $list | sed -n '/^150$/,$p'

The edge case is tricky because "equal or lower" can't be expressed with regex cleanly, so even an awk solution would look kinda convoluted, so I personally prefer a for loop for readability's sake:

for i in $list; do
    if [ "$i" -le "$threshold" ]; then
        head="$i"
    else
        tail="$tail\n$i"
    fi
done

printf '%b\n' "$head$tail"
[–] [email protected] 0 points 2 days ago (2 children)

For the first code snippet to run correctly, $list would need to be put in double quotes: echo "$list" | ... , because otherwise echo will conflate the various lines into a single line.

The for loop approach is indeed quite readable. To make it solve the original task (which here means that it should also assign a number just smaller than $threshold to $tail, if $threshold is not itself contained in $list), one will have to do something in the spirit of what @[email protected] and I describe in these comments.

[–] [email protected] 0 points 2 days ago (1 children)

The quoting oversight was due to me testing the first one only on zsh, which quotes differently.

The second was tested on Busybox ash and dash against the input in the example. It does assign a number just smaller or equal to threshold because head is overwritten on each iteration until it lands on the last value that was less than or equal to the threshold.

[–] [email protected] 0 points 2 days ago

Ah that's good to know about zsh.

Sorry regarding the second code block; it does indeed work as intended, and quite elegantly.