this post was submitted on 14 Jul 2024
0 points (NaN% liked)
A place for everything about math
900 readers
1 users here now
founded 5 years ago
MODERATORS
you are viewing a single comment's thread
view the rest of the comments
view the rest of the comments
This may not be the simplest, but here's an easy way to just use lots of substitution and basic algebra.
Let t = time in days to meet
Let a = speed (not velocity) of rocket A
Let b = speed (not velocity) of rocket B
1 = 200 * a
1 = 150 * b
200a = 150b
a = (3/4)b
1 = (t * a) + (t - 30) * b
Substitute for a
1 = (3/4)bt + bt - 30b = (7/4)b - 30b
Recall that 1 = 150 * b and set these equal
150b = (7/4 * t - 30) b
Divide by b
150 = 1.75t - 30
1.75t = 180
t ~ 103 days
At 103 days, the ships will meet, and since it's over half the time it takes for rocket A to reach Earth, the meeting point will be closer to Earth.