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submitted 3 months ago by [email protected] to c/[email protected]

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[–] [email protected] 9 points 3 months ago* (last edited 3 months ago) (3 children)

Yes. Typically, to multiply two n-bit numbers, you need n - 1 n-bit adders. You basically do long multiplication.

I'd upload an image but either voyager or my instance won't let me for some reason, so sorry if this doesn't embed right

[–] [email protected] 2 points 3 months ago

Shouldn't you be able to get away with two 2n bit adders and recursion?

[–] [email protected] 3 points 3 months ago

I'd upload an image but either voyager or my instance won't let me for some reason, so sorry if this doesn't embed right

Embedded just fine on my end (Jerboa)

[–] [email protected] 3 points 3 months ago

this makes sense