Programming Horror

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submitted 11 months ago* (last edited 11 months ago) by [email protected] to c/[email protected]

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[–] [email protected] 0 points 11 months ago* (last edited 11 months ago) (5 children)

modulo

pseudocode:

if number % 2 == 0
  return "number is even" (is_num_even = 1 or true)
else
  return "number is odd" (is_num_even = 0 or false)

plus you'd want an input validation beforehand

[–] [email protected] 0 points 11 months ago* (last edited 11 months ago) (1 children)

who needs modulo when you can get less characters out of

while (number > 1) {
  number -= 2;
}
return number;

very efficient

edit: or theres the trusty iseven api

[–] [email protected] 0 points 11 months ago (1 children)

here is somewhat less:

return (number % 2) == 0;

[–] [email protected] 0 points 11 months ago

return !(number & 1);

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