this post was submitted on 24 Dec 2024
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Day 24: Crossed Wires

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FAQ

top 12 comments
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[โ€“] [email protected] 2 points 15 hours ago* (last edited 15 hours ago)

Haskell, programmatic solution

I spent an entire day on this because I didn't write a unit test to check my "swap outputs" function, which effectively did nothing.

In any case: the approach (which may be more interesting than the code, I know people were interested) involved probing the addition circuit with some example additions - that is, I wrote something that'd let me give alternative inputs from x & y and compute the result using the circuit. I then gave it some simple pairs of values that'd exercise the add and carry bits (ie, pairs chosen from {i << n, n <- {1..43}, i <- {1, 3}}). That gave me some breaking trials.

Because the errors were relatively sparse, I then scanned over pairs of outputs, swapping those that didn't introduce a data dependency and checking (a) that no new errors were introduced over the trial sets, (b) for any reduction in the number of errors found. I got a bunch fo outputs like this:

swap of ("ccp","mnh") improves matters
bad trial count reduced from 346 to 344

which found the pairs for me. The search could be improved by more carefully tying the probe inputs to the outputs' dependencies (ie, if the first error comes from the (xi, yi) input bits, then look for swaps of the dependencies introduced by zi) - but in any case, it finds the answer. Phew.

[โ€“] [email protected] 2 points 15 hours ago

Rust + Pen and Paper

Yikers. Part 2 took a while, staring at this diagram for hours. Eventually I noticed that each of these blocks has two pairs of (XOR, AND) gates sharing the same inputs (and inputs aren't changed). So I matched up these pairs based on a distance metric of how much needs to be swapped to fit together. This helped me identify 4 blocks with errors, the rest was solved using pen and paper (one block is missing as it became apparent at that point):

shaky diagrams for full adder with wrong outputs

There is also some code, but do yourself and me a favor and don't look at it. While it does turn up the correct solution, it probably won't with any other input, especially not the examples.

[โ€“] [email protected] 1 points 22 hours ago (1 children)

Oh my Kernigan, that was stressful. Really worried about not finishing there.

Considered several approaches, the coolest of which would have been to test individual bits, propagate 'suspicion', etc, but it seemed too tricky.

Eventually I needed to go do something other than worry about not finishing so I started writing a validator for the adder structure. Just a couple of rules later I had found 4 faults already and managed to write automated fixups for them!

This means my solver is quite specific to my input but it can potentially be made more complete and I didn't 'cheat' by hardcoding manual graph analysis.

Code

#include "common.h"

/*
 * The approach behind part 2 was to essentially write a bunch of
 * validation rules for the structure of the adder, and then writing
 * fixups for problems it would find. That means it's likely quite
 * tailored to my input, but at least it's not hardcoding manual graph
 * analysis.
 */

enum { W_NULL, W_OFF, W_ON };

struct wire;

struct wire {
	struct wire *in[2];
	char name[4];
	char op; 		/* [A]ND, [O]R, [X]OR */
	int8_t val;		/* W_NULL, W_OFF, W_ON */
};

static struct wire wires[320];
static struct wire *zs[46], *swapped[8];
static int nw, nsw;

static struct wire *
get_wire(const char *name)
{
	int i;

	for (i=0; i<nw; i++)
		if (!strcmp(name, wires[i].name))
			return &wires[i];

	assert(nw < (int)LEN(wires));
	assert(strlen(name) < LEN(wires[i].name));

	snprintf(wires[nw].name, sizeof(wires[nw].name), "%s", name);
	return &wires[nw++];
}


static int
cmp_wires(const void *a, const void *b)
{
	struct wire * const *wa = a;
	struct wire * const *wb = b;

	return strcmp((*wa)->name, (*wb)->name);
}

static int
eval(struct wire *wire)
{
	int in1,in2;

	if (wire->val)
		return wire->val == W_ON;

	assert(wire->in[0]);
	assert(wire->in[1]);

	in1 = eval(wire->in[0]);
	in2 = eval(wire->in[1]);

	wire->val = W_OFF + (
	    wire->op=='A' ? in1 && in2 :
	    wire->op=='O' ? in1 || in2 :
	    wire->op=='X' ? in1 != in2 : (assert(!"bad op"), -1));

	return wire->val == W_ON;
}

static void
swap(struct wire *a, struct wire *b)
{
	struct wire tmp;

	//printf("swapping %s and %s\n", a->name, b->name);

	tmp = *a;

	a->op = b->op;
	a->in[0] = b->in[0];
	a->in[1] = b->in[1];

	b->op = tmp.op;
	b->in[0] = tmp.in[0];
	b->in[1] = tmp.in[1];

	assert(nsw+2 <= (int)LEN(swapped));
	swapped[nsw++] = a;
	swapped[nsw++] = b;
}

static struct wire *
find_z_xor(int bit)
{
	struct wire *xy_xor;
	int i;

	for (i=0; i<nw; i++) {
		 /* must be a XOR */
		if (wires[i].op != 'X')
			continue;

		 /* with an input XOR */
		xy_xor = wires[i].in[0]->op == 'X' ? wires[i].in[0] :
		         wires[i].in[1]->op == 'X' ? wires[i].in[1] :
		         NULL;
		if (!xy_xor)
			continue;

		 /* connected to the X and Y */
		if (xy_xor->in[0]->name[0] != 'x' &&
		    xy_xor->in[0]->name[0] != 'y')
			continue;

		 /* with the same bit number */
		if (atoi(xy_xor->in[0]->name+1) != bit)
			continue;

		return &wires[i];
	}

	return NULL;
}

static struct wire *
find_xy_and(int bit)
{
	int i;

	for (i=0; i<nw; i++) {
		 /* must be AND */
		if (wires[i].op != 'A')
			continue;

		 /* must have XY inputs */
		if ((wires[i].in[0]->name[0] != 'x'  ||
		     wires[i].in[1]->name[0] != 'y') &&
		    (wires[i].in[0]->name[0] != 'y'  ||
		     wires[i].in[1]->name[0] != 'x'))
			continue;
		
		 /* with the right bit number */
		if (atoi(wires[i].in[0]->name+1) != bit ||
		    atoi(wires[i].in[0]->name+1) != bit)
			continue;
		
		return &wires[i];
	}

	return NULL;
}

static void
fsck_carry_or(struct wire *or, int bit)
{
	struct wire *wire;
	int i;

	 /* both inputs must be AND; no fixup if neither */
	assert(
	    or->in[0]->op == 'A' ||
	    or->in[1]->op == 'A');

	for (i=0; i<2; i++) {
		if (or->in[i]->op == 'A')
			continue;

		//printf("carry OR parent %s not AND\n", or->in[i]->name);

		 /* only have fixup for the XY AND */
		assert(
		    or->in[!i]->in[0]->name[0] != 'x' &&
		    or->in[!i]->in[0]->name[0] != 'y');

		wire = find_xy_and(bit);
		assert(wire);
		swap(or->in[i], wire);
	}
}

static void
fsck_z(struct wire *z)
{
	struct wire *wire, *carry_or;
	int bit;

	assert(z->name[0] == 'z');

	bit = atoi(z->name+1);

	 /* first bit is very different */
	if (!bit)
		return;

	 /* for the final bit, Z is the carry OR */
	if (!zs[bit+1]) {
		 /* no fixup if it isn't */
		assert(z->op == 'O');

		fsck_carry_or(z, bit-1);
		return;
	}

	 /* must be a XOR */
	if (z->op != 'X') {
		//printf("Z %s isn't XOR\n", z->name);
		wire = find_z_xor(bit);
		assert(wire);
		swap(z, wire);
	}

	 /* bit 2 and up must have a carry OR */
	if (bit > 1) {
		carry_or =
		    z->in[0]->op == 'O' ? z->in[0] :
		    z->in[1]->op == 'O' ? z->in[1] : NULL;
		assert(carry_or);
		fsck_carry_or(carry_or, bit-1);
	}
}

int
main(int argc, char **argv)
{
	struct wire *wire;
	char buf[64], *rest, *lf, *name1,*name2, *opstr;
	uint64_t p1=0;
	int bit, i;

	if (argc > 1)
		DISCARD(freopen(argv[1], "r", stdin));

	while ((rest = fgets(buf, sizeof(buf), stdin))) {
		if (!strchr(buf, ':'))
			break;

		wire = get_wire(strsep(&rest, ":"));
		wire->val = W_OFF + atoi(rest);

	}

	while ((rest = fgets(buf, sizeof(buf), stdin))) {
		if ((lf = strchr(buf, '\n')))
			*lf = '\0';

		name1 = strsep(&rest, " ");
		opstr = strsep(&rest, " ");
		name2 = strsep(&rest, " ");
		strsep(&rest, " ");

		wire = get_wire(rest);
		wire->in[0] = get_wire(name1);
		wire->in[1] = get_wire(name2);
		wire->op = opstr[0];
	}

	for (i=0; i<nw; i++)
		if (wires[i].name[0] == 'z') {
			bit = atoi(&wires[i].name[1]);
			assert(bit >= 0);
			assert(bit < (int)LEN(zs));
			zs[bit] = &wires[i];
		}

	for (i=0; i < (int)LEN(zs); i++)
		if (zs[i])
			p1 |= (uint64_t)eval(zs[i]) << i;

	for (i=0; i < (int)LEN(zs); i++)
		if (zs[i])
			fsck_z(zs[i]);

	qsort(swapped, nsw, sizeof(*swapped), cmp_wires);

	printf("24: %"PRIu64, p1);

	for (i=0; i<nsw; i++)
		printf(i ? ",%s" : " %s", swapped[i]->name);

	putchar('\n');
	return 0;
}

https://codeberg.org/sjmulder/aoc/src/branch/master/2024/c/day24.c

Btw, spending some time on getting Graphviz output right did make studying the structure much easier!

Graph snippet

[โ€“] [email protected] 1 points 21 hours ago

I fiddled for ages to get nice graphviz output, that looks a lot nicer

[โ€“] [email protected] 1 points 1 day ago* (last edited 23 hours ago)

Haskell

For completeness' sake. I actually solved part 2 by looking at the structure with Graphviz and checking the input manually for errors. So the code here merely replicates the checks I was doing by hand.

solution

import Control.Arrow
import Control.Monad
import Data.Bifoldable
import Data.Bits
import Data.List
import Data.Map (Map)
import Data.Map qualified as Map
import Data.Maybe
import Data.Set (Set)
import Data.Set qualified as Set
import Text.Printf

data Op = AND | OR | XOR deriving (Read, Show, Eq)

readInput :: String -> (Map String Int, Map String (Op, (String, String)))
readInput s =
  let (inputs, gates) = second (drop 1) $ break null $ lines s
   in ( Map.fromList $ map (break (== ':') >>> (id *** read . drop 2)) inputs,
        Map.fromList $ map (words >>> \[a, op, b, _, o] -> (o, (read op, (a, b)))) gates
      )

evalNetwork :: Map String Int -> Map String (Op, (String, String)) -> Maybe Int
evalNetwork inputs gates = fromBits <$> getOutput signals
  where
    getOutput = traverse snd . takeWhile (("z" `isPrefixOf`) . fst) . Map.toDescList
    fromBits = foldl' (\a b -> (a `shiftL` 1) .|. b) 0
    signals = Map.union (Just <$> inputs) $ Map.mapWithKey getSignal gates
    getSignal w (op, (a, b)) = doGate op <$> join (signals Map.!? a) <*> join (signals Map.!? b)
    doGate AND = (.&.)
    doGate OR = (.|.)
    doGate XOR = xor

findError :: [(String, (Op, (String, String)))] -> Maybe (String, String)
findError gates = findGate AND ("x00", "y00") >>= go 1 . fst
  where
    go i carryIn = do
      let [x, y, z] = map (: printf "%02d" (i :: Int)) ['x', 'y', 'z']
      xor1 <- fst <$> findGate XOR (x, y)
      and1 <- fst <$> findGate AND (x, y)
      let layer2 = findGates (carryIn, xor1) ++ findGates (carryIn, and1)
      xorGate2 <- find ((== XOR) . fst . snd) layer2
      andGate2 <- find ((== AND) . fst . snd) layer2
      let xor2 = fst xorGate2
          and2 = fst andGate2
      orGate <-
        find
          ( \(_, (op, (a, b))) ->
              op == OR && any (`elem` [a, b]) [xor1, and1, xor2, and2]
          )
          gates
      msum
        [ checkIs xor1 =<< otherInput carryIn xorGate2,
          checkIs z xor2,
          go (succ i) (fst orGate)
        ]
    checkIs p q = (p, q) <$ guard (p /= q)
    otherInput x (_, (_, (a, b)))
      | a == x = Just b
      | b == x = Just a
      | otherwise = Nothing
    findGates (a, b) = filter (\(_, (_, ins)) -> ins `elem` [(a, b), (b, a)]) gates
    findGate op = find ((== op) . fst . snd) . findGates

part2 = sort . concatMap biList . unfoldr go . Map.assocs
  where
    go gates = (\p -> (p, first (exchange p) <$> gates)) <$> findError gates
    exchange (a, b) c
      | c == a = b
      | c == b = a
      | otherwise = c

main = do
  (inputs, gates) <- readInput <$> readFile "input24"
  print . fromJust $ evalNetwork inputs gates
  putStrLn . intercalate "," $ part2 gates

[โ€“] [email protected] 2 points 1 day ago* (last edited 1 day ago)

Javascript

Part one was easy, though despite starting at midnight I only placed 1786 for part one. I think my tendency to want to do OOP makes it take longer...

Part two.. Well, I figured it was some sort of binary circuit for trying to add binary numbers. So I hoped that the sum of the x registers and the y registers was the expected result of simulating the circuit like in part one. I later verified that it is the expected result.

I didn't want to try and manually figure out the bad outputs, coffee wasn't helping, I wanted sleep. So I uh.. I wrote logic to randomly create swaps. And then just hoped RNG got me covered. To help my chances, I ran it on 8 different processes.

When I woke up in the morning I discovered 8 stopped processes, each with "a solution" that was different. Turns out, if you just randomly swap wires at some point you get a system that outputs the desired result - but only because you sufficiently screwed it up more to produce the expected result, even if the system itself would not work for other input.

I could probably change the registers to another value, run it, and see if they match, thus ruling out an incorrect set of swaps causing a correct result with the original binary inputs. But at this point I just decided to do it the manual way following advice on here. My brain is fried, I'm stepping away to take a shower and get ready to visit family.

I had really hoped the bruteforce would work, I modified the bruteforce to run even after it finds a match and I'll let it run while I'm gone today and see if RNG produces any correct result at some point - I just fear the exponential answer timeout will prevent me from submitting these correctly incorrect combinations lol. I might modify it later with my theory above and just run it on a server indefinitely and see if it produces the correct result eventually.

https://blocks.programming.dev/Zikeji/9e4d6e81595d4845b88cf98eb91852d8

Edit:

Created a raw multithreaded bruteforce variant: topaz

[โ€“] [email protected] 3 points 1 day ago* (last edited 1 day ago)

Dart

Not very happy with this, as for part 2 the code just told me which four pairs of bits of the output needed investigation and I then tediously worked through how they differed from the correct adder implementation in the debugger.

Spoilered as it is overly long and not very interesting.

spoiler

import 'package:collection/collection.dart';
import 'package:more/more.dart';

var nodes = <String, Node>{};

class Node {
  String name = '';
  bool? state;
  var outputGates = <String>[];
}

class Wire implements Node {
  @override
  String name;
  @override
  bool? state;
  @override
  var outputGates = <String>[];
  Wire(this.name, this.state);
  set() {
    for (var g in outputGates) {
      (nodes[g]! as Gate).set();
    }
  }
}

class Gate implements Node {
  String input1, input2, type;
  @override
  String name;
  @override
  bool? state;
  @override
  var outputGates = <String>[];
  Gate(this.name, this.input1, this.input2, this.type);
  set() {
    var a = nodes[input1]!.state;
    var b = nodes[input2]!.state;
    if (a == null || b == null) return;
    state = switch (type) { 'AND' => a && b, 'OR' => a || b, _ => a ^ b };
    for (var g in outputGates) {
      (nodes[g]! as Gate).set();
    }
  }
}

void setup(List<String> lines) {
  var parts = lines.splitAfter((e) => e.isEmpty);
  Map<String, Node> wires = Map.fromEntries(parts.first.skipLast(1).map((e) {
    var p = e.split(': ');
    return MapEntry(p[0], Wire(p[0], p[1] == '1'));
  }));
  nodes = Map.fromEntries(parts.last.map((e) {
    var p = e.split(' ');
    return MapEntry(p.last, Gate(p.last, p[0], p[2], p[1]));
  }));
  nodes.addAll(wires);
  for (var g in nodes.values) {
    if (g is! Gate) continue;
    nodes[g.input1]!.outputGates.add(g.name);
    nodes[g.input2]!.outputGates.add(g.name);
  }
}

String line(String s) => nodes.keys
    .where((e) => e.startsWith(s))
    .sorted()
    .reversed
    .map((e) => nodes[e]!.state! ? '1' : '0')
    .join('');

part1(List<String> lines) {
  setup(lines);
  nodes.values.whereType<Wire>().forEach((e) => e.set());
  return int.parse(line('z'), radix: 2);
}

part2(List<String> lines) {
  setup(lines);
  var bits = nodes.keys.count((e) => e.startsWith('x'));
  for (var b in 0.to(bits)) {
    nodes.values.whereType<Gate>().forEach((e) => e.state = null);
    nodes.values.whereType<Wire>().forEach(((e) => e.state = false));
    nodes['y${b.toString().padLeft(2, "0")}']!.state = true;
    nodes.values.whereType<Wire>().forEach((e) => e.set());
    print('${line("x")}\t${line("y")}\t${line("z")}\t$b');
    var output = line('z');
    for (var i in 0.to(bits)) {
      if (output[bits - i] != ((i == b) ? "1" : "0")) print(i);
    }
  }
  tree('z05');
  tree('z06');
  // Add break point here and inspect and solve manually using `tree`.
  print('break here');
}

tree(String s, {indent = ''}) {
  var here = nodes[s]!;
  if (here is Wire) {
    print('$indent${here.name} (wire)');
    return;
  }
  here as Gate;
  print('$indent${here.name} ${here.type}');
  tree(here.input1, indent: indent + '| ');
  tree(here.input2, indent: indent + '| ');
}

[โ€“] [email protected] 3 points 1 day ago

Haskell

For part2 I compared the bits in the solution of part1 with the sum of x and y. With that, I could check the bits that did not match in a graphviz diagram and work from there.

code

import Control.Arrow
import Control.Monad.RWS
import Data.Bits (shiftL)
import Data.Char (digitToInt)
import Data.Functor
import Data.List
import Data.Map qualified as M
import Data.Tuple
import Text.ParserCombinators.ReadP hiding (get)
import Text.ParserCombinators.ReadP qualified as ReadP

type Cable = String
data Connection = And Cable Cable | Or Cable Cable | Xor Cable Cable deriving (Show)

cable = count 3 ReadP.get
eol = char '\n'
initial :: ReadP (M.Map Cable Bool)
initial = M.fromList <$> endBy ((,) <$> cable <*> (string ": " *> (toEnum . digitToInt <$> ReadP.get))) eol
wires = M.fromList <$> endBy wire eol

wire = do
    a <- cable <* char ' '
    op <- choice [string "AND" $> And, string "OR" $> Or, string "XOR" $> Xor]
    b <- char ' ' *> cable
    c <- string " -> " *> cable
    return (c, op a b)

parse = fst . last . readP_to_S ((,) <$> initial <*> (eol *> wires <* eof))

type Problem = RWS (M.Map Cable Connection) () (M.Map Cable Bool)

getConnection :: Connection -> Problem Bool
getConnection (And a b) = (&&) <$> getWire a <*> getWire b
getConnection (Or a b) = (||) <$> getWire a <*> getWire b
getConnection (Xor a b) = xor <$> getWire a <*> getWire b

xor True False = True
xor False True = True
xor _ _ = False

getWire :: Cable -> Problem Bool
getWire cable = do
    let computed = do
            a <- asks (M.! cable) >>= getConnection
            modify (M.insert cable a)
            return a
    gets (M.!? cable) >>= maybe computed return

fromBin :: [Bool] -> Int
fromBin = sum . fmap fst . filter snd . zip (iterate (`shiftL` 1) 1)

toBin :: Int -> [Bool]
toBin = unfoldr (\v -> if v == 0 then Nothing else Just (first (== 1) (swap (divMod v 2))))

part1 initial wiring = fst $ evalRWS (mapM getWire zs) wiring initial
  where
    zs = filter ((== 'z') . head) . sort $ M.keys wiring

part2 initial wiring = fmap fst . filter snd $ zip [0..] (zipWith (/=) p1 expect)
  where
    xs = fromBin . fmap (initial M.!) . filter ((== 'x') . head) $ sort $ M.keys initial
    ys = fromBin . fmap (initial M.!) . filter ((== 'y') . head) $ sort $ M.keys initial
    zs = filter ((== 'z') . head) . sort $ M.keys wiring

    p1 = part1 initial wiring
    expect = toBin $ xs + ys

main = getContents >>= print . (fromBin . uncurry part1 &&& uncurry part2) . parse

[โ€“] [email protected] 4 points 1 day ago (1 children)

Haskell bits and pieces

The nice thing about Haskell's laziness (assuming you use Data.Map rather than Data.Map.Strict) is that the laziness can do a ton of the work for you - you might've spotted a few Haskell solutions in earlier days' threads that use this kind of trick (eg for tabling/memoisation). Here's my evaluation function:

eval l =
  let
    v = l & Map.map (\case
                       Const x -> x
                       And a b -> v Map.! a && v Map.! b
                       Or a b  -> v Map.! a || v Map.! b
                       Xor a b -> v Map.! a /= v Map.! b)
  in v

For part 2, we know what the graph should look like (it's just a binary adder); I think this is a maximal common subgraph problem, but I'm still reading around that at the mo. I'd love to know if there's a trick to this.

[โ€“] [email protected] 2 points 1 day ago (1 children)

Thank you for showing this trick, I knew Haskell was lazy but this one blew my mind again.

[โ€“] [email protected] 3 points 1 day ago

Yeah, I remember when I saw this for the first time. It's astonishing how powerful lazy evaluation can be at times.

[โ€“] [email protected] 3 points 1 day ago

Haskell

Part 1 was trivial, just apply the operations and delay certain ones until you have all the inputs you need.

Code

import Control.Arrow
import Data.Bits
import Numeric

import qualified Data.Char as Char
import qualified Data.List as List
import qualified Data.Map as Map

parse s = (Map.fromList inputs, equations)
        where
                ls = lines s
                inputs = map (take 3 &&& (== "1") . drop 5) . takeWhile (/= "") $ ls
                equations = map words . filter (/= "") . tail . dropWhile (/= "") $ ls

operations = Map.fromList
        [ ("AND", (&&))
        , ("XOR", xor)
        , ("OR", (||))
        ]

solveEquations is []     = is
solveEquations is (e:es)
        | is Map.!? input1 == Nothing = solveEquations is (es ++ [e])
        | is Map.!? input2 == Nothing = solveEquations is (es ++ [e])
        | otherwise      = solveEquations (Map.insert output (opfunc value1 value2) is) es
        where
                value1 = is Map.! input1
                value2 = is Map.! input2
                opfunc = operations Map.! operation
                (input1:operation:input2:_:output:[]) = e

wireNumber prefix = List.filter ((prefix `List.isPrefixOf`) . fst)
        >>> flip zip [0..]
        >>> List.filter (snd . fst)
        >>> List.map ((2 ^ ). snd)
        >>> sum

part1 = uncurry solveEquations
        >>> Map.toList
        >>> wireNumber "z"

part2 (is, es) = List.intercalate "," . List.sort . words $ "z08 ffj dwp kfm z22 gjh jdr z31"

main = getContents
        >>= print
        . (part1 &&& part2)
        . parse

For part 2 I tried symbolic solving to detect discrepancies but I wouldn't achieve anything with it.

SymbolicEquation

data SymbolicEquation = Single { eqName :: String }
        | Combine
        { eqName :: String
        , eqOperation :: String
        , eqLeft :: SymbolicEquation
        , eqRight :: SymbolicEquation
        }
        deriving (Eq)

instance Show SymbolicEquation where
        show (Single name) = name
        show (Combine name op l r) = "(" ++ name ++ "= " ++ show l ++ " " ++ op ++ " " ++ show r ++ ")"

symbolicSolve is [] = is
symbolicSolve is (e:es)
        | is Map.!? input1 == Nothing = symbolicSolve is (es ++ [e])
        | is Map.!? input2 == Nothing = symbolicSolve is (es ++ [e])
        | otherwise = symbolicSolve (Map.insert output (Combine output operation value1 value2) is) es
        where
                value1 = is Map.! input1
                value2 = is Map.! input2
                (input1:operation:input2:_:output:[]) = e

My solution was to use the dotEngine-function to translate the operations into a digraph in graphviz-style which I simply plotted and searched through using a python script.

dotEngine

dotEngine (input1:operation:input2:_:output:[]) = [
          input1 ++ " -> " ++ output ++ " [ label=" ++ operation ++ "];"
        , input2 ++ " -> " ++ output ++ " [ label=" ++ operation ++ "];"
        ]

I took a loook at the initial graph which was a vertical line with a few exception which I figured would be the misordered wires. I did try some hardware-simulations in the far past to build bit-adders which helped me recognize patterns like carry calculation. First I replaced all occurences of x__ XOR y__ -> w with x__ XOR y__ -> xor__ to recognize them more easily. The same with AND of xs and ys. Using the following script I would then use some Regex to search for the rules that corresponded to carry calculations or structures I knew. The script would break exactly four times and I would then figure out what to switch by hand through looking at the updated graphViz.

Please excuse the bad coding style in the script, I had written it on the ipython-REPL.

python script

r = open("input").read()
for i in range(2, 45):
    prevI = str(i - 1).zfill(2)
    I = str(i).zfill(2)
    forward = f"xor{I} AND carry{prevI} -> (\\w+)"
    backward = f"carry{prevI} AND xor{I} -> (\\w+)"
    m1 = re.search(forward, r)
    m2 = re.search(backward, r)
    if m1 is None and m2 is None:
        print(forward, backward)
        break
    m = m1 or m2
    r = r.replace(m.group(1), f"combinedCarry{I}")
    forward = f"and{I} OR combinedCarry{I} -> (\\w+)"
    backward = f"combinedCarry{I} OR and{I} -> (\\w+)"
    m1 = re.search(forward, r)
    m2 = re.search(backward, r)
    if m1 is None and m2 is None:
        print(forward, backward)
        break
    m = m1 or m2
    r = r.replace(m.group(1), f"carry{I}")
open("input", "w").write()

When solving such a swapped wire problem I would then use my haskell function to plot it out again and stare at it for a few minutes until I understood wich parts belonged where.

The last one looked like this
GraphViz of the last set of problem wires

In this one I needed to switch jdr and carry31 to make it work.