this post was submitted on 21 Mar 2024
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So, I was doing this:

ffmpeg -i /media/johann/5461-000B/DCIM/100MEDIA/IMAG0079.AVI -ss 00:00:00 -t 00:00:20 ~/Public/240321/240321_0079.avi ; rm /media/johann/5461-000B/DCIM/100MEDIA/IMAG0079.AVI

one at a time changing the IMAG0079 to IMAG0080 etc every time. I am sure there must be a way to perform two actions (ffmpg) and (rm) on each file in a folder. Can anyone help (For next time)

Thanks!

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[–] [email protected] 14 points 7 months ago (1 children)

What about something like this:

for i in /media/johann/5461-000B/DCIM/100MEDIA/*.AVI; do newpath="$HOME/Public/240321/$(basename "$i" | sed 's/^IMAG/240321_/g')"; ffmpeg -i "$i" -ss 00:00:00 -t 00:00:20 "$newpath" && rm "$i"; done
[–] [email protected] 7 points 7 months ago* (last edited 7 months ago)

Awesome! Thanks, I knew there had to be a way!

edit: This also works: for i in *.avi; do ffmpeg -i "$i" -ss 00:00:00 -t 00:00:10 ~/Public/test/${i%.*}.avi ; done

But yours is much nicer.

[–] [email protected] 4 points 7 months ago

Try this:

for file in ./*
do
    echo "$file"
done

To do some substitution operation om the filename you can use Bash Parameter Expansion.

[–] [email protected] 2 points 7 months ago (1 children)

Use another folder instead of name

[–] [email protected] 1 points 7 months ago (1 children)

The input filename changes each time.

[–] [email protected] 0 points 7 months ago* (last edited 7 months ago) (1 children)
find -name "*.avi" | while read file;
do
  echo -v "$file"
done

edited

[–] [email protected] 3 points 7 months ago

Almost, here is the one that worked: for i in *.avi; do ffmpeg -i "$i" -ss 00:00:00 -t 00:00:10 ~/Public/test/${i%.*}.avi ; done

Thanks for pointing me in the right direction.