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How exactly does linux use prefix length assigned to network interface? (lemmy.world)

submitted 9 months ago by [email protected] to c/[email protected]

20 comments fedilink hide all child comments

I was exploring direct links between machines, and basically failed to break something.

I assigned IP address 192.168.0.1/24 to eth0 in two ways.

A. Adding 192.168.0.1/24 as usual

# ip addr add 192.168.0.1/24 dev eth0
# ping -c 1 192.168.0.2
PING 192.168.0.2 (192.168.0.2) 56(84) bytes of data.
64 bytes from 192.168.0.2: icmp_seq=1 ttl=64 time=0.051 ms

***
192.168.0.2 ping statistics
***
1 packets transmitted, 1 received, 0% packet loss, time 0ms
rtt min/avg/max/mdev = 0.051/0.051/0.051/0.000 ms
#

B: Adding 192.168.0.1/32 and adding a /24 route

# ip addr add 192.168.0.1/32 dev eth0
# # 192.168.0.2 should not be reachable.
# ping -c 1 192.168.0.2
ping: connect: Network is unreachable
# # But after adding a route, it is.
# ip route add 192.168.0.0/24 dev eth0
# ping -c 1 192.168.0.2
PING 192.168.0.2 (192.168.0.2) 56(84) bytes of data.
64 bytes from 192.168.0.2: icmp_seq=1 ttl=64 time=0.053 ms

***
192.168.0.2 ping statistics
***
1 packets transmitted, 1 received, 0% packet loss, time 0ms
rtt min/avg/max/mdev = 0.053/0.053/0.053/0.000 ms
#

Does this mean that adding an IP address with prefix is just a shorthand for adding the IP address with /32 prefix and adding a route afterwards? That is, does the prefix length has no meaning and the real work is done by the route entries?

Or is there any functional difference between the two methods?

Here is another case, these two nodes can reach each other via direct connection (no router in between) but don't share a subnet.

Node 1:

# ip addr add 192.168.0.1/24 dev eth0
# ip route add 192.168.1.0/24 dev eth0
# # Finish the config on Node B
# nc 192.168.1.1 8080 &lt;&lt;&lt; "Message from 192.168.0.1"
Response from 192.168.1.1

Node 2:

# ip addr add 192.168.1.1/24 dev eth0
# ip route add 192.168.0.0/24 dev eth0
# # Finish the config on Node A
# nc -l 0.0.0.0 8080 &lt;&lt;&lt; "Response from 192.168.1.1"
Message from 192.168.0.1

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[–] [email protected] 10 points 9 months ago (13 children)

First: it seems you got some things mixed up. 192.168.0.1/24 isn’t a IP address, strictly speaking. It’s Network information wich translates to „your IP is 192.168.0.1 and your subnet mask is 255.255.255.0“. The /dd is the amount of bits set in the subnet mask. An within the first and last address are reserved for network and broadcast. With your /32 assignments you basically told your system, it has no network to talk to.

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